Sentence examples for dn 1 from inspiring English sources

Exact(6)

So the number must be less than 2. Thus, Dn, 1 > Dn, 2.

Letting λ N 1, λ N 2, · · ·, λ N k, denote the eigenvalues of the noise image of the characters and λ DN 1, λ DN 2, · · ·, λ DN k, denote the eigenvalues of denoised characters, the summation of the ratio between noise and denoised character energies in different subspaces can be denoted as E = ∑ i = 1 k λ N i λ DN i (5).

In the case that T has at least n 1 + d / log 2 (t + 1 ) subsets whose sizes are bounded from above by d, then when i = dn 1 + d / log 2 (t + 1 ), both Q old and Q new have at most 2 dn 1 + d / log 2 (t + 1 ) = ((t + 1 ) 1 1 + log 2 (t + 1 ) / d ) n elements.

There is currently no generally accepted definition for renal hyperfiltration (29), but it is increasingly recognized that elevated GFR is an early hemodynamic abnormality seen in diabetes that is linked with an increased risk of DN (1).

However, it is still unclear whether these 2 complications are related to or affect each other or whether both of them progress simultaneously after their onset, although many epidemiological studies have shown the coexistence of DR and DN (1, 2).

Hence, when i > dn 1 + d / log 2 (t + 1 ), all elements in Q old or in Q new have at most (t + 1 ) n - n 1 + d / log 2 (t + 1 ) combinations of h i t(H), i.e., the size of Q old or Q new is always bounded from above by (t + 1 ) n - n 1 + d / log 2 (t + 1 ) = ((t + 1 ) 1 1 + log 2 (t + 1 ) / d ) n. Therefore, the total time complexity is O (((t + 1 ) 1 1 + log 2 (t + 1 ) / d ) n mnt ).

Similar(54)

Then, by the nth row derived to the (n − 1 th row, it is easy to know Dn − 1, 1 > Dn − 1, 2. And so on, get Di, 1 > Di, 2. Therefore, the nodes in the first row have the largest forwarding number of data packets.

As applications, the maximal and minimal ranks of the generalized Schur complement A - BM 1)C - DN(1 G and the partial matrix (A BM 1)C DN(1 G) with respect to the generalized inverse M 1) ∈ M{1} and N(1) ∈ N{1} are also considered.

As applications, we derive the extremal ranks of the generalized Schur complement A - BM 1)C - DN(1 G and the partial matrix (A BM 1)C DN(1 G) with respect to the generalized inverse M 1) ε M{1} and N(1) ∈ N{1}.

As direct applications of the results in Section 2, we determine in this section the maximal and minimal ranks of the generalized Schur complement A-BM 1 C-DN(1)G A-BM 1 C-DNtiA-BM 1 C-DNA BM(1 G DN(1)G) with respect to two vandantheatrices M(1) ∈ M{1} and N(1) ∈ N{1}.

From the proof of Theorem 3.1, we known that A - BM 1)C - DN(1 G = A1 - BF m W1C - BW2E m C - DF N W3G - DW4E N G, where A1 = A - BM†C - DN†G.

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