Sentence examples for discrete obstacle from inspiring English sources

An active set strategy is also an efficient way to solve discrete obstacle problems, see, for example, [11 13].

The first auxiliary problem proposed in [17] plays an important role in connecting the continuous and discrete obstacle problems.

In Section 3, the SOR is applied for both linear and nonlinear problems and analyzed for convergence; the limits of iterates are proved to satisfy discrete obstacle problems.

Then it would satisfy the discrete obstacle problem (3.5), particularly (widehat{u}_{pq}gevarphi_{pq}) at all (interior) grid points (mathbf{x}_{pq}in varOmega _{h}^{0}).

Based on some kind of active set strategy, the discrete obstacle problem can be reduced to a sequence of linear problems, which are then solved by some efficient methods.

Then the second kind of auxiliary obstacle problem is introduced to establish a relationship between the discrete obstacle problem (32) and the first auxiliary obstacle problem (34): left { textstylebegin{array}{l} mbox{Find } bar{{u}}_{kh}inbar{K}_{kh} mbox{ such that} bar{u}_{kh}= argmin_{vinbar{K}_{kh}} J_{h} v), end{array}displaystyle right.

Laboratory tests, as well as field tests, over discrete obstacles and uneven hard surfaces were conducted.

Still, the ability to overcome discrete obstacles on a steep slope is very different depending on the wheel that is facing the obstacle.

Some areas are plotted as obstacles, in these datasets number of discrete obstacles have been drawn to consider obstacles in synthetic data sets for Test-data-110 data set (third row of Table 1) and the number of continuous and discrete obstacles have been drawn for Test-data-200 data set (fourth row of Table 1).

A unique characteristic of equiatomic alloys is the absence of "solvent" and "solute" atoms, resulting in a breakdown of the textbook picture of dislocations moving through a solvent lattice and encountering discrete solute obstacles.

Consider the discrete two-sided obstacle problem of finding (uin K) such that textstylebegin{cases} (Au+f u))_{i}geq0&mbox{if } u_{i}=phi_{i}, (Au+f u))_{i}= 0&mbox{if } phi_{i}< u_{i}< psi_{i}, (Au+f u))_{i}leq0&mbox{if } u_{i}=psi_{i}, end{cases} (5.1) where A and f are defined as before, (K={vin R^{n}:phileq vleqpsi}) with (phi<psi).