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Hence we deduce that there exists v ∈ X such that y = Tv.
From (3.12), for, we deduce that there exists a positive integer number large enough, when, (3.32).
From (2.6) (with z = z1), we deduce that there exists p1 ≥ y + x such that.
In light of (2.12) and (2.13), we deduce that there exists some such that (2.14).
As in the proof of Theorem 4.9, we deduce that there exists satisfying (3.4).
We can now apply Theorem 2.6 to deduce that there exists x with (x=g(x)).
In order to deduce that there exists a positive constant (K_{T}) uniform w.r.t.
For an AB-multiresolution analysis associated with any expanding matrices, we deduce that there exists a singe scaling function in its reducing subspace.
By continuity, we deduce that there exists (t_{gamma}in 0,1)) such that (|gamma(t_{gamma})|_{E}=rho).
Being a closed subset of, repeating the same argument, we deduce that there exists a point such that.
By applying the Banach contraction principle, we deduce that there exists a unique (eta^in X) such that (eta^=Teta^).
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CEO of Professional Science Editing for Scientists @ prosciediting.com