Sentence examples for cross partial from inspiring English sources

The relaxing single-crossing or Spence-Mirrlees condition is the constant sign of the cross partial derivative with respect to decision and type: (CS+) ∀ (q,θ) in Q × Θ : V ̂ q θ > 0, (CS–) ∀ (q,θ) in Q × Θ : V ̂ q θ < 0. This implies that the existence of a curve q0 dividing the (θ,q) plane into two single-crossing regions, with V q θ > 0 below q0 and V q θ < 0 above.

With U regarded as a function U S, V), its differential dU is      (40) A comparison with the preceding equation shows immediately that the partial derivatives are     (41) Furthermore, the cross partial derivatives,     (42) must be equal because the order of differentiation in calculating the second derivatives of U does not matter.

The latter has an interaction that makes the cross partial derivative positive, so the function is not simply additive.

However, although all strains used in the present crossing experiments are identical in the ITS2 sequence, the crossing ability among them shows three different patterns which are successful crossing, partial or complete gamete incompatibility (Fig. 5).

Parameters (gamma _3) and (gamma _4) are reduced forms of the cross-partial derivative of (u(w_{kt},d_{jk})) evaluated at sample means.

I use these to examine whether and how the agents' treatment changes in order to estimate the cross-partial derivative in (3).

Without any further considerations the results suggest that an increase in the mean of the distribution of this characteristic reduced the cross-partial derivative in (3).

Karaca-Mandic, Norton and Dowd [34] explained that the significance of interaction terms indicates improvement of the goodness of fit of the model, while it does not indicate a significance of a cross-partial effect, and the sign of interaction terms is not the sign of a cross-partial effect.

Per the cross-partial derivative in equations (8) and (9), if the off-farm labor allocation decision of the spouse is independent of the operator, then ∂ E s ∂ E o = ∂ E o ∂ E s = 0.

To compute the cross-partial derivatives, we used '-margins' command in Stata [ 33].

Since the logit coefficient in the non-linear model cannot be used for interpreting interaction terms, we computed cross-partial derivatives to interpret the interaction terms [ 33, 34].