Sentence examples for continuous s from inspiring English sources

The time and phase response in continuous (s) domain and pole-zero distribution in discrete (z) domain are used as measurement metric in the present study.

(Tx+Syin K) whenever (x,yin K); T is compact and continuous; S is a contraction mapping.

Since S is continuous, S 2 x 3 n → S u ( n → ∞ ), S A x 3 n → S u ( n → ∞ ).

In the continuous s. c. infusion protocol, 40 subjects received rGLP-1 at 0.0, 1.5, 2.5, 3.5, and 4.5 pmol/kg/min for 10-12 hovernightnight starting one hour after the evening meal.

T is sequentially weakly continuous, S is a strict contraction, there are an integer n 0 and a vector x 0 ∈ E such that T is S-power-convex condensing w.r.t.

S′L and S′R are not necessarily continuous: S ' L = S L if S L does not cross the main content S L − S cross + S E if S L crosses the main content.

The following removal of the salts and urea in water created the sponges composed of interconnected pores and the continuous S-sulfo keratin matrix.

When treated at low-temperatures (≤ 420 °C), the microstructure is dominated by nitrogen supersaturated martensite (α'N-expanded martensite); Nitrogen S-phase grains can be formed from the pre-existent retained austenite by converting the retained austenite grains in 17-4PH but no continuous S-phase layer was found.

FESEM micrographs of both lower and upper surfaces of the films reveal that the s-1,2-PB lamellae pass through i-PP convex regions from the bottom, i.e. the dispersed i-PP regions lie on the continuous s-1,2-PB phase.

For the blends, TEM and AFM observations show that with addition of i-PP, the s-1,2-PB long lamellae become bended and i-PP itself tends to form dispersed convex regions on a continuous s-1,2-PB phase even when i-PP is the predominant component, which indicates a strong phase separation between the two polymers during film formation.

Let (T, S) be partially weakly increasing, order limit preserving and weakly compatible pair such that dominating map T is weak annihilator of S. If T is continuous, S-ordered nonexpansive and S is affine, then Fix(T) ∩ Fix(S) is nonempty provided that for a nondecreasing sequence {x n } with x n → u implies that x n ≤ u.