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By continuity, S k t Ψ + θ b t Ŝ k − 1 ≠ 0 for all Θ in a small neighborhood of the LMS attractor.
Proof From the construction of the expression S 4 ( u h, φ ) it follows that u ˆ h = u h on Π h, and u ˆ h = φ j on γ j h, j = 1, 2, 3, 4. The continuity of u ˆ h on Π follows from the continuity S 4 ( u h, φ ) on each closed triangle Type A and Type B, and from the equality u ˆ h = u h on Π h.
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Similarly, taking the continuity of S, we can show that S z = z.
It is worth mentioning that the notions of p-continuity and p s -continuity for a self-mapping on X are incomparable in general.
Using the uniformly continuity of S i, we obtain (3.21).
By the continuity of G ( ⋅, s ) and (H4), then (3.6) holds.
In our subsequent result, the p s -continuity plays a central role.
Moreover, the continuity of f implies S is continuous.
Now "continuity" is Mr Hatoyama's watchword.
Continuity is strategy's fifth test.
Stability theory deals with the continuity of W ∗ and S ∗.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com