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Firstly, the operator T is continuous in view of the continuity of functions (f t,u(t))) and (G t,s)).
By the continuity of functions f and g, the operator T is continuous.
By continuity of functions f and g, the operator T is continuous.
By continuity of functions f and g, the operator (mathcal{T}) is continuous.
The continuity of functions f and g imply that the operator (mathcal{K}) is continuous.
The lesson chosen addresses the topic of continuity of functions at a point.
Similar(29)
With the help of the continuity of mapping function, spectrum values other than can be also obtained.
Note that continuity of function (property (e)) was not used.
The continuity of function f iε (i = 1, 2) also shows that (2.9).
From the continuity of function θ and hypothesis (HC3) and (HD), we have: (3.3).
This obviously contradicts the uniform continuity of function f x0, ω), where ω = ∑ I ω I dx I with -n ≤ ω I ≤ n for any I.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com