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If H ( z, f ) just contains one term of maximal total degree, then for any ε > 0, m ( r, P ( z, f ) ) = O ( r σ − 1 + ε ) + S ( r, f ).
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Sending a query containing one term to other databases is usually sufficient, so the number of single term queries sent to PubMed might have been overestimated.
Also, and both contain one term.
Suppose that P ( z, f ) is a difference polynomial of the form (1.1) and contains exactly one term of maximal total degree in f ( z ) and its shifts.
Moreover, we assume that U ( z, f ) contains just one term of maximal total degree in f ( z ) and its shifts.
If H zz, f ) contains just one term of maximal total degree, then for any ε > 0, m ( r, P ( z, f ) ) = O ( r ρ - 1 + ε ) + S ( r, f ), possibly outside of an exceptional set of finite logarithmic measure.
If (H z,f)) contains just one term of maximal total degree, then for any small enough (varepsilon>0), m bigl r,P z,f) bigr)=O bigl(r^{rho-1+varepsilon} bigr)+S r,f).
If U ( z, f ) contains just one term of maximal total degree in f ( z ) and its shifts, then, for each ε > 0, m ( r, P ( z, f ) ) = O ( r ρ − 1 + ε ) + S ( r, f ), possibly outside of an exceptional set of finite logarithmic measure.
Moreover, we assume that all coefficients a λ ( z ) in (2.2) are small in the sense that T ( r, a λ ) = S ( r, f ) and that U ( z, f ) contains just one term of maximal total degree in f ( z ) and its shifts.
If the Taylor series of f contains at least one term of the form c k, 0 z 1 k with c k, 0 ≠ 0 and k ≥ 2 or of the form c 0, j z 2 j with c 0, j ≠ 0 and j ≥ 2, then for all n ≥ n 0 we have ∥ R n, n q 1, q 2 ( f ) − f ∥ r 1, r 2 ∼ ( a n + 1 b n ).
(That last sentence contains one of the most shocking misuses of the term "incident" that I have ever witnessed).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com