Sentence examples for conservation reading from inspiring English sources

Exact(1)

Reprinted in Roderick Nash, The American Environment: Readings in The History of Conservation (Reading, Mass.: Addison-Wesley Publishing Company, 1968).

Similar(59)

For more on the film project and turtle conservation, read the students' blog or follow the project on Twitter via @pacebaja.

The cutoff to determine homologous sequences is a position-specific conservation (read, distance) metric for homologs based on classical information theory (log220).

It appears that both simple and complex AS patterns have functional importance in view of the two different forms of selection pressure (protein sequence conservation and reading frame preservation) for which they are constrained.

Learn more about carnivore conservation by reading The Carnivore Way: Coexisting with and Conserving North America's Predators, and The Wolf's Tooth: Keystone Predators, Trophic Cascades, and Biodiversity by Dr. Cristina Eisenberg.

In addition, based on iTSS locations shortly behind the annotated start codon and the conservation of reading frames, our data allowed the reannotation of the 5′ ends of 46 reading frames in Synechocystis 6803 (Supplementary Table S2).

GenBank numbers for all sequence data included are given in Additional file 2. All protein-coding genes were aligned using MUSCLE [ 51], and subsequently translated to ensure conservation of reading frame.

Using Equation (9), the particle-number conservation condition reads Ψ N Ψ = 2 ∑ j > 0 2 B 1 j 2 + B p j 2 + B n j 2 + 2 B 4 j 2. Open image in new window (12).

In the case of an even-odd system, the particle-number conservation condition reads, using the state (11) ν t N ν t = 1 + 2 ∑ j > 0 j ≠ ν 2 B 1 j 2 + B p j 2 + B n j 2 + 2 B 4 j 2. Open image in new window (15).

In the case of an even odd system, the particle-number conservation condition reads, using the state (11) ν T N ν T = 1 + 2 ∑ j > 0 j ≠ ν 2 ( B 1 j ) 2 + B p j 2 + B n j 2 + 2 B 4 j 2 (15)As for the gap parameters, they are given by Δ t t ν = - G t t ∑ j > 0 j ≠ ν B 1 j B t j + B 5 j B t ′ j ( t = n, p, t ′ ≠ t ) Δ n p ν = 2 G n p ∑ j > 0 j ≠ ν B 4 j B 1 j - B 5 j (16).

Using Eq. (9), the particle-number conservation condition reads: Ψ N Ψ = 2 ∑ j > 0 2 ( B 1 j ) 2 + B p j 2 + B n j 2 + 2 B 4 j 2 (12)In the same way, the gap parameters defined by (7) become Δ t t = - G t t ∑ j > 0 B 1 j B t j + B 5 j B t ′ j ( t = n, p, t ′ ≠ t ) Δ n p = - G n p ∑ j > 0 B 4 j B 1 j - B 5 j (13).

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