Sentence examples for computation in case from inspiring English sources

The core idea is to store enough information to restart computation in case of an error.

not applied, BP seconds spent for block partitioning, SB seconds spent for the single block iteration, CB seconds spent for the combining of deblurred block images, IN the iteration number that attained the smallest RSE, and PC seconds spent for the parallel computation in case when NB processing units are used.

The method also facilitates numerical computation in cases where an explicit solution cannot be found.

We used ICCs because it has been shown that with data that are rated as a dichotomy, the ICC is equivalent to measures of nominal agreement, simplifying computation in cases where more than two raters are involved [ 15].

Fig. 9. Examples of computation results in Case 1.

Sire-mgs models offer a good compromise between accurate modelling of the genetic part and computation requirements in case the data structure is not adequate to use an animal model.

In this case, we have (see relevant computations in cases I and II) p ( k − m ) = p ( k ) − 1, p ( k + 1 ) = p ( k ). and q ( k − n ) = q ( k ), q ( k + 1 ) = q ( k ) + 1.

Using the 3D Pro/E software, the paper makes models of the flow passage components of first stage prototype of CCP in nuclear power stations, and completes the cavitation steady-state computation in the case that the high flow rate of first stage prototype reaches Q = 160 m3/h using the numerical computation software ANSYS CFX.

We continue to describe the improved computation in the case where both input strings s and t are of length at least 2. To do so, we first add some auxiliary notation.

In addition to this (see relevant computations performed in case I), we have q ( k − n ) = q ( k ) − 1 and q ( k + 1 ) = q ( k ).

Like with the computations performed in case I, we can get ( k − m − m i − n j i + j + 1 ) = 0 if  i ≥ 0, j ≥ q ( k − m ). and ( k − n − m i − n j i + j + 1 ) = 0 if  i ≥ p ( k − n ), j ≥ 0. So, we can substitute q ( k ) for q ( k − m ) in (23) and p ( k ) for p ( k − n ) in (24).