Sentence examples for completeness due from inspiring English sources

The catalogue is expected to be complete for M ≥ 4 for the whole period, but to show a decreasing magnitude of completeness due to improvement of the seismograph network over the period.

With the help of a suitable modification of its proof, we deduce a characterization of Smyth complete quasi-metric spaces which provides a quasi-metric generalization of the well-known characterization of metric completeness due to Kirk.

It maintains a high degree of completeness due to mandatory reporting by both clinicians and pathologists/cytologists (Mattsson and Wallgren, 1984; National Board of Health and Welfare, 1996).

For completeness, due to previous research linking amygdala dysfunction to psychopathic traits, we inspected whether neural responses in amygdala varied as a function of psychopathic traits.

After performing a CC analysis, all covariates in the model became less significant irrespective of their completeness, due to the reduction in sample size.

The traditional monitoring systems lack either in completeness due to an unsystematic approach [ 16] or lack in representativity due to a selective study design (cf. [ 17, 18] as examples for studies in single hospitals).

Not surprisingly, the set of general predicate tautologies of each of these logics is Σ1-complete (due to completeness theorem).

Next, the weak compactness of implies that is weakly compact and hence complete due to completeness of (see [3]).

The weak compactness of implies that is weakly compact and hence -sequentially complete due to completeness of.

Next, the weak compactness of wcl ( T ( M ) ) implies that wcl ( T n ( M ) ) is weakly compact and hence complete due to completeness of X. From Theorem 3.5, for each n ≥ 1, there is a unique x n in M such that x n = f ( x n ) = g ( x n ) = T n ( x n ).

The weak compactness of wcl ( T ( M ) ) implies that wcl ( T n ( M ) ) is weakly compact and hence complete due to completeness of X. From Theorem 3.5 for each n ≥ 1, there exists a unique x n ∈ F ( f ) ∩ F ( g ) such that x n = f ( x n ) = g ( x n ) = T n ( x n ).