Sentence examples for compatible one of from inspiring English sources

{ f, S } and { g, T } are weakly compatible; one of fX, gX, SX and TX is a closed subspace of X, then f, g, S and T have a common fixed point.

f X ⊆ T X ; g X ⊆ S X ; L a − ϕ ( a, a, a ) < 0 for all a > 0 ; f is dominating and weak annihilator of T; g is dominating and weak annihilator of S; { f, S } and { g, T } are weakly compatible; one of fX, gX, SX and TX is a closed subspace of X.

f X ⊆ T X ; g X ⊆ S X ; f is dominating and weak annihilator of T; g is dominating and weak annihilator of S; { f, S } and { g, T } are weakly compatible; one of fX, gX, SX and TX is a closed subspace of X.

In that case, there are two possible solutions: the reproduction of the old mortar or the production of a compatible one.

We show that the interaction has the characteristics of a compatible one, with expanding rather than limited lesions.

Amino acids are inherently compatible, and one of the common amino acids is l-arginine, which has zwitterionic structure.

If for a nondecreasing sequence { x n } with x n ⪯ y n for all n but finitely many and y n → u implies that x n ⪯ u, and furthermore (1) { f, S } and { g, T } are weakly compatible;   (2) one of fX, gX, SX and TX is a closed subspace of X,  .

This is disappointing for something that claims it's compatible with one of the most ubiquitous text formats around and the thought of spending $300 and then having to reformat and/or convert many of the files you want to read is silly.

holds for any two comparable elements x, y ∈ X. Suppose that f, g, S and T satisfy the following conditions: (1) f X ⊆ T X ;   (2) g X ⊆ S X ;   (3) f is dominating and weak annihilator of T;   (4) g is dominating and weak annihilator of S;   (5) { f, S } and { g, T } are weakly compatible;   (6) one of fX, gX, SX and TX is a closed subspace of X.  .

Each of these analyses could only visit trees compatible with one of the two compared hypotheses (i.e., Ecdysozoa or Coelomata).

Obviously, a SNP matrix M is feasible if and only if there are two haplotypes such that every row of M is compatible with one of the two haplotypes.