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We claim that g x = g u.
We claim that g w = g v.
Now, we claim that g u = t.
We claim that g ( t x ) = t g ( x ).
Finally, we claim that g z = g g z.
Finally, we claim that g u = g g u.
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We did not find, nor did we claim, that BPA-G has estrogenic activity.
Step 2. We claim that { g x n } is right-Cauchy in ( X, q ), that is, for all ε > 0, there is n 0 ∈ N such that q ( g x n, g x m ) ≤ ε for all m > n ≥ n 0. We reason by contradiction.
It has been claimed that G-BOAD's flight from London Heathrow to Boston set a transatlantic flight record of 3 hours, 5 minutes, 34 seconds.
Since T u 0 ∈ T ( X ) ⊆ g ( X ), there exists u 1 ∈ X such that g u 1 = T u 0. Repeating this process, there exists a sequence { u m } m ≥ 0 such that g u m + 1 = T u m for all m ≥ 0. We claim that { g u m } → d g x and { g u m } �� d g y.
Hence by Theorem 2.1, IVEP has a solution on B = K ∩ co ( co U ∪ { y 0 } ) ¯. Then there exists x ∗ ∈ B such that f ( g ( x ∗ ), y ) ∉ − int C ( x ∗ ), ∀ y ∈ B. We claim that f ( g ( x ∗ ), y ) ∉ − int C ( x ∗ ), ∀ y ∈ K. Indeed, if the sentence is not true then there is y ∈ K so that f ( g ( x ∗ ), y ) ∈ − int C ( x ∗ ).
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com