Sentence examples for circle communication from inspiring English sources
For the record, the difference between Group Text and say, Twitter, is the tie-in with location awareness and closed circle communication.
When the degree K of sensor is 1 and the number of sensors is 10, the figure shows deployment of sensors, sensing range and number of neighboring sensors that are maintained on average (pink circle: sensing range, orange circle: communication range, green circle: supersonic wave range).
"It does give the perception of how tight the circle of communication and influence is between his role as mayor and as the owner of a major business," Mr. Dadey added.
At the center of Simon's "golden circle" of communication is the core... the "WHY".
The art world has a great propensity to take its own incestuous circles of communication as exercising significant leverage on the 'real world'.
Of all the C words circulating through education circles (including communication, collaboration, courage and critical thinking), perhaps the most important is creativity.
"UNICEF welcomes the 4As initiative to create new circles of communication on children's rights amongst advertising and communication students".
BestPosition for node i must be the intersection of communication circle of any two nodes in NT i) or the intersection of the line ij and communication circle of node j.
The orchestra itself celebrates a virtuosity of listening, an experience that extends to the audience, who complete a charmed circle of musical communication.
Instead of marking each interaction with an X, we used three symbols to reflect the varying frequency of team interactions: a large circle for daily communication, a midsize circle for weekly meetings, and a small dot for monthly conferences.
In fact, when node p is in the region I, the value of Sp is equal to the area of communication circle of node p. When node p is inside the area II, the value of Sp is equal to the communication circle area π r t 2 minus the area of arch S ACBD, so: P d min G > 0 = 1 − e − nπ r t 2 / l 2 4 n r t l − r t / l 2 × ∏ ∀ p ∈ Ω II 1 − e − n S p / Ω (26).
