Sentence examples for cells number of from inspiring English sources

Exact(39)

We quantify the clustering process by measuring the area fraction covered by the cells, number of cell aggregates, and their average size as a function of time.

Histological evaluation of skin sections exposed to SM revealed that the time to onset and the severity of symptoms including disorganization of epidermal basal cells, number of pyknotic nuclei, activation of mast cells and neutrophils dermal invasion were dose-dependent.

The key parameters considered in this study are: number of cells, number of lanes, span length, number and area of cross-bracing and top-chord systems, and truck(s) speed and truck(s) positioning.

Additional side effects and participitans' health status were checked three times during the study by measuring standard haematological parameters (number of white and red blood cells, number of platelets) and clinical chemistry for liver function (ALAT, ASAT, γGT and total bilirubin), kidney function (creatinin) and inflammation (C-reactive protein).

Digital image analysis of the bread crumb showed that the total number of cells, number of small cells and total cell area of the bread crumb ranged from about 22 to 27 cm−3, 20 to 25 cm−3 and 12% to 29%, respectively.

It is equal to co-channel cells number of f i existing correlative traffic.

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Similar(21)

$$\end{document} % viable cells = 1.00 – Number of blue cells ÷ Number of total cells × 100.

Cell seeding efficiency in the scaffolds was evaluated by counting the nonadhered cells using a hemocytometer as following equation: (2) Cell    seeding    efficiency      = [ (number of    seeded    cells −     number    of    nonadhered    cells    to    the    scaffold ) × (number    of    seeded    cells ) − 1 ] × 100.

For SA- β-gal-positive staining cell quantification, 100 cells were counted on three separate fields and the mean of blue-stained cells was calculated as followed (number of blue cells/(number of total cells)).

The percentage of cell viability was calculated as ((number of unstained cells)/(number of total cells)) × 100.

In five random 20 × fields per well, the percentage of proliferative cells was calculated as follows: (number of BrdU positive cells/ number of PI positive nuclei) × 100%.

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