Sentence examples for cd which contains from inspiring English sources

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DNMT1 comprises a regulatory N-terminal domain (NTD), which covers two-thirds of the molecule, and a C-terminal catalytic domain (CD), which contains all essential motifs of active C5 DNA methyltransferases.

A special "Experience Edition" CD, which contains a 28 page booklet, unseen footage from Minogue's 2009 For You, For Me tour, behind the scenes footage of the promotional photo and video shoots of the album, an exclusive interview, and a previously unreleased bonus track entitled "Mighty Rivers", was also released on the same day.

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Phase C, which contains the heaviest concentration of artifacts and human occupation debris in the stratigraphy, comprises of a rapidly deposited, heterogeneous mixture of dark colored, organic-rich sandy silty loams.

From the AFM image of sample C, which contains annealed InAs QD layers, dashes and holes are clearly visible.

The testing data is divided into test set C, which contains simulated reverberant data with multiplicative and additive noise, and test set D, which contains real reverberant data.

The reader can find the method find_nodes described in Algorithm 2. Before continuing, we have to define the vector C, which contains a set of vectors.

Note that ℱ is nonempty since C ∈ F. Set L = ⋂ M ∈ F M. The set L is an admissible subset of C which contains D. Using the definition of ℱ, we deduce that L is T-invariant.

Felicity condition: D w) ⊈ Ct (The set of φ-worlds is not a subset of C, which contains all ¬φ-worlds pre-established in C by the speaker at t, and t < t@.)  .

To begin with, we dedicate one vector per control C which contains the identity of the involved queues (e.g., the flow it belongs to and/or the state) and the identities of the packets enqueued at the involved queues.

For any n ≥ 1, set K n = conv ¯ { y t ; t ≥ n }, where conv ¯ ( A ) is the intersection of all closed convex subset of C, which contains A ⊂ C. Since C is itself closed and convex, we get K n ⊂ C for any n ≥ 1. Property (R) will then imply ⋂ K n ≠ ∅.

For any n ≥ 1, let us set K n = conv ¯ ρ { h t ; t ≥ n }, where conv ¯ ρ ( A ) is the intersection of all ρ-closed convex subset of C, which contains A ⊂ C. Since C is itself ρ-closed and convex, we get K n ⊂ C for any n ≥ 1. Property (R) will then imply ⋂ K n ≠ ∅.

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