Sentence examples for can be compared based on from inspiring English sources

Molecules can be compared based on their 2D molecular structure [8, 9].

They differ in the direction in which the single-hop channels and are measured and can be compared based on two observations.

Also from these data, simplified average multi-linear plots derived from all the experiments can be compared based on different test specimen and loading types, leading to aggregate findings about various distinctive structural behaviors exhibited.

Indicator species analysis finds both dominant and non-dominant species that have high specificity and fidelity to a given class using a permutation test to assign an indicator value and associated p-value to those species (Dufrene and Legendre 1997) and any set of alternative classifications can be compared based on those metrics (Dufrene and Legendre 1997).

Hence, different architectures can be compared based on their sensitivity to attacks, and the method can be used to guide decision both in architecting the system-of-systems and in planning updates and modifications, accounting for the impact of interdependencies on the robustness of the system-of-systems.

Genes can be compared based on the terms that they are annotated with in the GO.

We know that many differential forms can not be compared based on the above definition since there are so many inequalities to be satisfied.

Each motif discovery program can then be compared based on the rate of true and false predictions.

Datasets can also be compared based on functional activity, allowing the detection of large-scale functional similarity between the effects of experimental perturbations (Figs 2 and 3).

Furthermore, studies that so far collected distinct measures of SWB can still be compared, based on the fact the distinct measures all load on a similar genetic factor, and thus represent biological overlapping constructs.

(3) I (A 1 & S & T ) − I (A 2 & S & T ) = log ⁡ (P (A 2 & S & T ) P (A 1 & S & T ) ) = log ⁡ (P (S & T ) P (A 2 | S & T ) P (S & T ) P (A 1 | S & T ) ) = log ⁡ (P (A 2 | S & T ) P (A 1 | S & T ) ) As a result, any two competing alignment hypotheses A 1 and A 2 can now be compared based on their message lengths.