Sentence examples for by introducing a new variable from inspiring English sources

Exact(14)

To overcome such shortcoming, the primary model was then extended by introducing a new variable FP to address the effect of cyclic softening feature.

Other models have differentiated between latent and active infected cells by introducing a new variable (w) for the latently infected cells [32 37].

Furthermore, by introducing a new variable z=x T x to linearize constraint (39c), the above problem can be relaxed to a standard SDP problem which yields the result of (14).

By introducing a new variable Y n = ( y n, y n − 1, …, y n − m ) T, we can rewrite (2.3) in the form Y n + 1 = F ( Y n, τ ), (2.4).

Combining (2) and (4), by introducing a new variable (zinmathbb{R}^{n}), we obtain the following regularized minimization problem: begin{aligned} minlimits _{x,zinmathbb{R}^{n}}&f_{lambda} x,z):=|x-z|^{2} +lambda|x |_{1} mbox{s.t.} &z=bigl[x- F x bigr]_, end{aligned} (5) where (lambda>0) is a regularization parameter and (|cdot|) is denoted as the Euclidean norm.

To investigate all traveling wave solutions of the FMKP equation (16), we transform it to a dynamical system by introducing a new variable (chi ) as follows: begin{aligned} chi = (leta +mY-Utau ), end{aligned} (17 where l and m are the cosines of the angles made by wave propagation with (eta )-axis and Y-axis, respectively.

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Similar(46)

But the rockets, though largely ineffective so far, are introducing a new variable into that calculation.

After introducing a new variable, the resulting coupled nonlinear integral differential equations are successfully solved by employing the extended system shooting method.

Introducing a new variable ξ = − P r s 2 e − s η, (36).

"You're introducing a new variable very quickly," explains Joe Holder, a Nike running coach and trainer and a performance coach at S-10 Training in New York City.

We do that by introducing a new fresh variable b i,j and the constraints: {small{begin{aligned} 0 leq b_{i,j} leq a_{i,j} qquad text{and} qquad a_{i,j}-1+p_{j} leq b_{i,j} leq p_{j}.

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