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The main results are that [L M] is lower semicontinuous in M but is not continuous.
It is easy to check that is order continuous, but is not continuous at.
Then satisfies the inequality (2.1) with and and has a unique fixed point, but is not continuous.
We would like to construct two set-valued mappings from (X times Y) to (mathbb{R}) that satisfy following conditions: One is a mapping that is quasi-convex in the first variable but is not continuous in second variable.
Coagulation necrosis is a less common sign, and appears as an echogenic focus within lymph nodes but is not continuous with the surrounding fat and does not produce acoustic shadowing [41], [42].
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Clearly, (mathcal{R}) is T-closed but T is not continuous.
is (( d_{e},leq ) )-nondecreasing-continuous on (mathbutR}), but it is not continuous at (x=0).
There exists a 2-metric space ( X, d ) such that every convergent sequence is a Cauchy sequence but d is not continuous (see [21]).
There exists a 2-metric space ( X, d ) such that every convergent sequence in it is a Cauchy sequence but d is not continuous; see [6]. .
There exists a 2-metric space ( X, d ) such that every convergent sequence is a Cauchy sequence but d is not continuous, see [[27], Remark 02 and Example 02]. .
(6) This function has a FP (x^=0) and is everywhere differentiable, but ∂ϕ is not continuous at 0. Because (rho (phi '(0) )=0), (5) is satisfied, and the iteration (1) converges locally to 0. Nevertheless, ϕ is not a local contraction at 0. To see this, note first that for any neighborhood (B 0,delta)) there exists (x in B) such that (phi'(x) =1).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com