Sentence examples for branches emanating from the from inspiring English sources

The degree of branching was determined by counting the number of branches emanating from the primary hyphae (33).

To add populations to this tree, we included them as branches emanating from the species tips; polytomies were thus created for species with more than 2 populations in the data set.

Changes in dendritic branching were more significant in basilar branches when compared with apical branches (Fig. 2D F), and the greatest plasticity was observed in the middle order branches (branch orders 3 7) rather than in branches emanating from the soma or at the dendrite extremities (Fig. 2E and F).

In this latter region, the visceral tracheal branches emanate from the segmentally repeated main lateral branches and do not abut the Ilp7 axons, suggesting paracrine growth regulation.

The branch emanating from the second eigenvalue is unique near the bifurcation point up to rotation.

We show that the odd-focusing peaks exhibit a split, where each sub-peak represents a population of a particular spin branch emanating from the injector.

Continuation of the bifurcated branch emanating from the first PD point exhibits unstable period-2 double-cluster states, consisting of two clusters having two neurons in each cluster (referred to as a split, where the notation means m neurons belong to one cluster and the remaining n neurons belong to the other).

Together with the observation that the constitutively active form of Gαs is ineffective in rescuing the wing expansion defects produced by Gαo overexpression (Table 2), these data suggest that the Gαs-cAMP-PKA pathway culminating at apoptosis is not the sole signaling branch emanating from the bursicon-rickets GPCR activation.

These subgroups, one fulfilling and one not fulfilling the condition in the split, appear graphically under a left and a right branch emanating from the group.

This SNP creates a branch emanating from the A.Br.008/009 node and currently contains only 3 isolates plus the prominent Sverdlovsk genotype.

(a) (y_{k}) is continuous at the nodes of the graph, i.e., in particular for our graph y_{k1}(0,lambda ) = y_{k2}(0,lambda ) = y_{k3}(0,lambda ); (8)   (b) the sum of the derivatives over all the branches emanating from a node, calculated for each node, is zero, y_{k1}^{prime }(0,lambda ) + y_{k2}^{prime }(0,lambda ) + y_{k3} ^{prime } 0, lambda ) = 0. (9)  .