Sentence examples for both submodules are equivalent from inspiring English sources

However, note that even for a general operator f → the number of equations can be reduced if the initial conditions of both submodules are equivalent (x → 10 = x → 20 ).

This is because both definitions are equivalent.

Therefore, both formulations are equivalent.

In [11], Wirsing proved that both classifications are equivalent.

If both methods are equivalent then  12 =0.5.

Wirsing [10] proved that both classifications are equivalent.

Note that both approaches are equivalent [ 51].

both of which are equivalent to (12).

Both are equivalent to saying "happy belated birthday" in English.

So, the correlation values are equivalent at both sides.

Then, the following statements are equivalent: (a) M has a family {S i }i∈Iof simple submodules such that M = ⊕ i ∈ I S i Open image in new window(d.s); (b) M has a family of simple submodules whose sum is M itself;   (a) every submodule of M is a direct summand of M.  .