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Binary regression analysis demonstrated a significant association (P < 0.045) of APACHE II scores >20 with Score to Door Times greater than the median 4 10 hours.
Binary regression analysis demonstrated an independent influence on choice of admitting hospital for the following factors: male sex, noncardiac cause of OHCA excluding trauma, transport with CPR in progress, as well as severe neurological compromise (CPC 3) prior to collapse (Table 1).
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Univariate binary logistic regression analysis demonstrated that the biomarkers are statistically significant predictors of hormonal response.
Multivariate binary logistic regression analysis demonstrated that TFF3 is an independent biomarker of endocrine response and degree of response, and this was confirmed in a validation cohort.
Multivariate binary logistical regression analysis demonstrated that the ability of TFF3 to discriminate which patients will respond to endocrine intervention is independent of the other parameters evaluated.
The results of the linear-by-linear association chi square test showed no linear trend in regard to class years of education although binary logistic regression analysis demonstrated that class years of education is significantly associated with breakfast consumption habits.
A Bayesian binary regression analysis was used to generate a predictor of oxaliplatin sensitivity from the gene expression data.
Pearson correlation coefficients, multiple linear regression analysis and binary regression analysis was conducted using spss Version 15 (SPSS, Inc., Chicago, Illinois).
Predictors of using alternative medicine were identified using logistic binary regression analysis.
Univariate and multivariate binary regression analysis was applied to identify predictors of AKI and WRF.
When all nine variables were included in a multivariable binary logistic regression analysis, two demonstrated a trend towards being independent risk factors: popliteal aneurysm (OR 2·24, 95percentnt c.i. 1·15 to 4·39; P = 0·018) and centre (Malmö: OR 2·68, 1·15 to 6·27; P = 0·023).
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