Sentence examples for because in this example from inspiring English sources

On the other hand, E2 would seem to provide much greater confirmation to H, because, in this example, it would be expected that Pi(E2/H /Pi(E2) >> Pi(E1/H /Pi(E1/H /Pi

This is in accord with the intuition because, in this example, more observations or datasets indicate more information as these simulated data are generated under quite similar circumstances.

In this example 1, most people may behave as the patient agent B. It is to be noted that both impulsive agent A and patient agent B may be rational, because, in this example 1 alone, there is no inconsistency even in impulsive agent A's behavior.

Because in this example the underlying mechanism is allostery, the CV term that corresponds to this mechanism (MI:1157, 'allostery') is used to name an interaction attribute.

Because in this example all 10 loci have a + allele in the "selected" population, (3) P = P r { n + = 10 | 2 ∑ G 1 ≥ R }.

The proportional reduction is the same for admissions and emergency visits because in this example the concentration response function is simply scaled based on the relative frequency of the two types of outcome.

This is because in these examples (the distorted and real field data), we neither expect nor seek to exactly fit the observed data (see the figures pertinent to Model 2 and Model 3).

Moreover, because we in this example keep the exposure prevalence in the population unchanged at 0.05, the incidence of D is reduced accordingly, in this example from 0.0240 to 0.0220.

Models generally do not predict boundary values well and removing all zero values is not appropriate because the zero in this example is an important response.

Note that if we put γ = ξ = 0 in the BCs of problem (1), then this new problem is more general than the previous one because in this case someone, for example, can take λ 1 [ x ] = γ x , λ 2 [ x ] = ξ x.

Because we take (l=2) in this example, the errors in the (L^{2}(L^{2})), (L^{2}(H^{1}) ), (L^{2}), and (H^{1} ) norms theoretically should have the third-order accuracy concerning k.