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Let k and j be two integers such that (k>jgeq0).
Let p and q be two integers such that (d=p^{2}-4qneq 0) (to exclude a degenerate case).
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Let M, N be two integers.
So, there are two integers k 1, k 2 such that 1 − t = 2 k 1, t = 2 k 2. Since 2 k 1 + 2 k 2 = 1, k i < 0 for all i = 1, 2. Thus, we may assume that 1 − t = 2 − n 1, t = 2 − n 2 and n 1 ≥ n 2 ∈ N without loss of generality.
Factor pairs are two integers which multiply together to make a particular number.
where s > r ≥ 1 are two integers.
Let n and m be any two integers such that (nge m), then begin{aligned} int _{-1}^{1}L_{n}(x L'_{m}(x){rm d}x= 0. end{aligned}.
Let n and m be any two integers such that (n-mle N) and (m>0), then begin{aligned} int _{-1}^{1}L_{n}(x L"_{n-m}(x){rm d}x= 0. end{aligned}.
Let n and m be any two integers such that (n,m le N), then begin{aligned}&(1) int _{-1}^{1}L'_{n}(x L_{m}(x){rm d}x=left{ begin{array}{ll} 2, & {rm if} n=m+i 0, & {rm if} nne m+i {rm or} nle m, end{array} right.
Corollary Let p be an odd prime with p ≡ 1 mod 4, then we have the identity p = ( ∑ a = 1 p − 1 2 ( a + r a ¯ p ) ) 2 + ( ∑ b = 1 p − 1 2 ( b + s b ¯ p ) ) 2, where r and s are any two integers such that ( r p ) ⋅ ( s p ) = − 1.
Let be two nonnegative integers such that.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com