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A closed and linear operator is said to be sectorial of type if there exist, and such that its resolvent exists outside the sector and,.
A closed and densely defined linear operator A is said to be sectorial of type ω ˜ if there exist 0 < θ < π / 2, M > 0, and ω ˜ ∈ R such that its resolvent exists outside the sector ω ˜ + S θ : = { ω ˜ + λ : λ ∈ C, | arg | < θ }, ∥ ( λ I − A ) − 1 ∥ ≤ M | λ − ω ˜ |, λ ∉ ω ˜ + S θ.
Recall that a closed and linear operator A is said to be sectorial of type
Similar(57)
Hence, is sectorial of type.
Assume that is sectorial of type.
Hence, is sectorial of type and (P1) is satisfied.
Clearly is densely defined in and is sectorial of type.
Assume that A is sectorial of type (omega<0).
Note that an operator A is sectorial of type ω if and only if (omega I-A) is sectorial of type 0. [89].
Assume that A is sectorial of type (omega<0) and (rhoin U_{infty}).
Assume that is sectorial of type and that conditions (H*1),(H*3), (H*4) and (H*5) hold.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com