Sentence examples similar to be dense in a from inspiring English sources

If (P f)) is dense in A, then (P bar{f})) is dense in (kappa(A)).

B is dense in A if A ⊆ A ∩ B ¯.

Then π ( M ) is dense in A ( S ).

Moreover, (P f cap A) is dense in A, which implies (operatorname{card}(P f cap A geq n+1).

Since (P f)) is dense in A, we have (P(A cap(B x,varepsilon cap A neqemptyset).

If A is a transitive set of ((X,f)) and (P f)) is dense in A, then A is an s-set of ((X,f)).

Then: (1) U is dense in A if U is a nonempty open set of X satisfying A ∩ U ≠ ∅ and ( f 1 n ) − 1 ( U ) ⊆ U for every n ∈ N.   (2) E = A or E is nowhere dense in A if E is a closed invariant subset of X and E ⊆ A.   (3) ⋃ n ∈ N f 1 n ( A ) is dense in A if A is a regular closed set of X.  .

Since (P f)) is dense in A, it follows that (P f cap(V_{i}cap A neqemptyset) for each (i=1,2,ldots,m).

(1.2). where, are closed linear operators defined on a common domain which is dense in a Banach space, and represent the Caputo derivative of defined by (1.3).

A point P i is dense in a subspace S, if |N S (P i )|≥τ i.e. it has at least τ neighbours within ε distance.

U is dense in A if U is a nonempty open set of X satisfying A ∩ U ≠ ∅ and ( f 1 n ) − 1 ( U ) ⊆ U for every n ∈ N. E = A or E is nowhere dense in A if E is a closed invariant subset of X and E ⊆ A. ⋃ n ∈ N f 1 n ( A ) is dense in A if A is a regular closed set of X. Proof (1) Since ( f 1 n ) − 1 ( U ) ⊆ U for every n ∈ N, we have ⋃ n ∈ N ( f 1 n ) − 1 ( U ) ⊆ U.