Your English writing platform
Discover LudwigSuggestions(2)
Exact(1)
Although Corollary 4.2 demands the function φ ∈ ( Φ 0 ) to imply that (4.7) holds by Definition 2.4(2), it does not require the t-norm of H-type to be continuous for all y ∈ X such that (4.8) holds.
Similar(59)
Then is continuous, for all, and (3.11).
(i) is continuous for all ; (ii).
(i) is continuous for all,, for all ; (ii), for all,. . is continuous for all,, for all ;, for all,.
(i) is continuous for all ; (ii)for all, one has.
(i) is continuous for all ; (ii) for each, and.
F is continuous for all ω ∈ Ω or.
If, then one has (i) is continuous for all,, for all ; (ii), for all,. . is continuous for all,, for all ;, for all,.
(i) is continuous for all,, for all ; (ii) (, for all, where (222) . is continuous for all,, for all ; (, for all, where (222).
Since (t_{i}) is continuous for all (i=1,2,ldots,N), it follows that (P_{D} I-lambda I-t_{i}))) is continuous for all (i=1,2,lD} I-lambda I-t_{i}
Since x → g ( ω, x ) is continuous for all ω ∈ Ω, we conclude that h is continuous for all ω ∈ Ω.
Write better and faster with AI suggestions while staying true to your unique style.
Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com