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Exact(1)
It is obvious that for Let be any nonzero solution of (2.14) such that for Let be such a constant that If the curve lays in for, then would have to be a strict egress point of with respect to the original system of coordinates.
Similar(59)
where is any nonzero solution of (2.1).
Let be any nonzero elements in with.
Then is additive and for all and all Let be any nonzero complex number.
Similarly, let (g=g(t)) be a nonzero solution of the linear equation g"(t)+f(t cdot g(t)=0, (2.5) and (Q=Q t,x)) be a function such that Q_{t}=a_{0}cdot gcdot e^{P}, qquad Q_{x}= biggl(frac{1}{2}a_{1}- frac {g'}{g} biggr gcdot e^{P}.
where is a nonzero solution of (2.1).
Then is a nonzero solution of (2.1).
It is easy to see that being a positive solution of BVP(1.2) is equivalent to being a nonzero solution equation as follows: (3.11).
Thus, (u_{lambda}^ in mathcal{N}_{lambda, M}(Omega)) is a nonzero solution of (1.1) and (mathcal{J}_{lambda, M} u_{lambda}^) ge c_{lambda}).
It is easy to see that u ∈ C 4 [ 0, 1 ] ∩ C 6 ( 0, 1 ), being a positive solution of (13), is equivalent to u ∈ Y +, being a nonzero solution of u = H F u. (21).
By (3.1 - 3.3 3.1 - 3.3asy to see that u ∈ C4[0,1] ∩ C6(0, 1) It a posisiveasylutoon of BVP (1.1) iff u ∈ Y+ isee nonzero soluthat of an operator equation as follows u = H F u. (3.9).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com