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Proof Let g be an unbounded solution of inequality (2.1).
Proof Assume x ( t ) > 0 be an unbounded solution of (1.1).
Proof For h to be an unbounded solution of inequality (2.5), we can choose a sequence { ( x n, y n ) | n ∈ N } in G 2 such that 0 ≠ | h ( x n, y n ) | → ∞ as n → ∞.
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This means that X is an unbounded solution of system (1).
Letting, boundary conditions imply that is an unbounded solution of BVP (1.1).
Then, f ̄ is an unbounded solution to both (2) and (3) with an arbitrary function ϕ : R → R+ subject to inf {ϕ(t) : t ∈ R} ≥ 2|b||1 - b|.
Let A be a Banach algebra of all diagonal 2 × 2 matrices with complex entries and let f ̄ : R → A be given by the formula f ̄ ( x ) : = f ( x ) 0 0 b, where f : R → A is an unbounded solution to (1) and b ∈ C {0,1} is arbitrarily fixed.
Let f be an unbounded modulus function.
Let f be an unbounded modulus.
Then, is an unbounded positive solution of BVP (1.1).
(3.4). is an unbounded positive solution of (1.1).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com