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[10] Let u be an inner function.
Let I be an inner function dividing I f.
(Aleksandrov) [1, Theorem 11 and Remark 2, p. 2915] Let (Theta ) be an inner function.
Assume X and Y are two spaces of analytic functions in the unit disk D with X ⊆ Y. Let θ be an inner function.
Using the following theorem in [5], we can exclude a much larger class of Blaschke products from being one-component inner functions: (Berman) Let u be an inner function.
Then, by Lemma 3, (Omega _u eta )) is connected for all (eta in [eta _0,1[). Choose (0be an inner function with (||u-Theta ||
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Theorem A Suppose that 0 < s < 1 and θ is an inner function.
end{aligned}Since u is an inner function, E has linear measure zero (by [5, Theorem 4.2]).
Corollary 1 Let 1 < p < ∞, 0 < t p < 1 and 0 < s < 1. Suppose θ is an inner function.
If θ is an inner function we write (I_{theta}) for (theta I_{n}) and (mathcal{Z}(theta)) for the set of all zeros of θ.
These assumptions hold for the system described in Section 3. By Appendix B, it follows that (T z)) is an inner function on (mathbb {C}^).
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be an intrinsic function
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