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Let be an arbitrary subsequence of.
Let be an arbitrary subsequence of Then there exists a subsequence of which converges weakly to a point.
Let w = { w i } i = 1 ∞ ∈ Λ Open image in new window and v = { v i } i = 1 ∞ ∈ Λ Open image in new window be an arbitrary subsequence of w.
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Since is an arbitrary subsequence of, we conclude that converges strongly to.
Since { v n } is an arbitrary subsequence of { x n }, therefore A ( { v n } ) = { v } for all subsequences { v n } of { x n }.
Since { u n } is an arbitrary subsequence of { x n }, we have A { u n } = { u } for all subsequences { u n } of { x n }.
Since { u n } is an arbitrary subsequence of { x n }, therefore A ( { u n } ) = { u } for all subsequence { u n } of { x n }.
Since { y n } is an arbitrary subsequence of { x n }, therefore, A C ( { y n } ) = { v } for all subsequence of { y n } of { x n }.
Since { x n k } is an arbitrary subsequence of { x n }, we can conclude that { x n } converges strongly to P F ( T ) ( x 0 ).
Since { x n k } is an arbitrary subsequence of { x n }, we can conclude that { x n } converges strongly to P F ( T ) ∩ EP ( f ) ( x 0 ).
Since { x n i } is an arbitrary subsequence of { x n }, we obtain that x n → Proj F x 1 as n → ∞.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.
Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com