Sentence examples for be acceptable if there from inspiring English sources

We define the IMRT planning system to be acceptable if there exists a common beam set such that dose distributions in PTVs and OARs are partly acceptable for all DVCs.

A finite collection of random variables (X_{1},X_{2},ldots,X_{n}) is said to be acceptable if there exists (delta>0) such that, for any real (|lambda|

(Table 2) Respondents agreed that post mortem needle biopsies would only be acceptable if there were a compelling reason to perform them.

The majority (27/42) found that deferred consent would be acceptable if there was a limited time frame for initiation of treatment, however 8 respondents found this unacceptable when the intervention was a new drug.

There was a general feeling that bed rails would be acceptable, if there was a risk the person might fall out of bed, as this participant with dementia said: Well, I'd be happy to have that for myself rather than fall.

Others thought it was unfair for those who could not afford to pay: "If I have money, I get served first, and if I am poor, I can wait forever?" (Lithuania) or that it would only be acceptable if there were two separate systems or if people who could pay went privately "People who can pay may do this but the doctors should deal with them after official working hours" (Estonia).

Paperbacks are acceptable if there is evidence of worthwhile thought and purpose.

Mr. Bush said today that financing such a program was acceptable if there was also a nonreligious alternative available to those seeking help.

Although the information rate is low when the fraction of errors is near 100%, the information rate is acceptable if there is a small penalty in the fraction of successful decoding.

We say that a finite collection of random variables X1, X2,..., X n is acceptable if there exists δ > 0 such that for any real λ∈, E exp λ ∑ i = 1 n X i ≤ ∏ i = 1 n E exp ( λ X i ).

We say that {X i : i ≥ 1} are acceptable if there exists δ > 0, such that for any real λ satisfying | λ | ≤ δ, E exp λ ∑ i = 1 n X i ≤ ∏ i = 1 n E exp { λ X i }, for all n ≥ 1. (1.1).