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If, then is said to be a regular point (of ) and the map is called conformal at.
Lemma 4.3 Let u ∈ A ad be a given element, and let y ∈ W 0 1, p be a regular point of the Lagrangian (4.1).
Proof Let y ∈ W 0 1, p be a regular point for the Lagrangian (4.1) and let h ∈ W 0 1, p be an arbitrary distribution.
Corollary 4.4 Let u ∈ A ad and λ ∈ W 0 1, p be given elements, and let y ∈ W 0 1, p be a regular point of the Lagrangian (4.1).
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Then 0 is a regular point with respect to (1.1).
Then we have the following assertions: (1) (x_{0}) is a regular point of (3.1).
therefore z 0 is a regular point in view of Theorem 4.1.
end{aligned} (38) From (38), it is clear that (r ( x,t ) ) is a regular surface, that is, every point of it is a regular point.
Therefore, 0 is a regular point if and only if (1.6) holds and hence Theorem 1.1 is completed.
It is natural to ask what condition the spine should satisfy to guarantee that (x_{0}) is a regular point.
0 is a regular point of the spectrum of the linear operator (-triangle+V_{i}) acting on (mathbf{L}^{2}), (i=1,2).
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com