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Firstly, we prove that f cannot be a rational function.
Lemma 3.5 Let k and l be positive integers, and let R be a rational function.
Let R be a rational function such that R' ≠ 0 on C.
Let (ngeq2) be an integer and (R z)) be a rational function.
Let f be a rational function and (Omega ={z:|f z)|<1}).
By (1.8) and (2.19), we see that f ( z ) cannot be a rational function.
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That is, it is given by an expression which is a rational function of its argument and some of the derivatives of the argument.
In this paper a model for 2-D real rational reactance functions is introduced which is a rational function in p1 and p2 where the coefficients are functions of parameters.
Let's suppose that I have a Laplace transform, and the Laplace transform that I'm talking about is a rational function, which is 1 over s plus 1 times s plus 2. Then the pole-zero pattern, as it's referred to, in the s-plane, the location of the roots of the numerator and denominator polynomials.
Then, f is a rational function.
where K = H ′ H + 2 G ′ G (42). is a rational function.
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