Sentence examples for be a measurable selection from inspiring English sources

Let be two measurable multivalued operators, be a constant and be a measurable selection of.

A mapping is said to be a measurable selection of a measurable mapping, if is measurable and a.e.

Let be two measurable multivalued operators, let be a constant, and let be a measurable selection of.

Let v 2 be a measurable selection for U (which exists by Kuratowski-Ryll-Nardzewski's selection theorem [21, 22]).

Let (u(cdot)) be a solution of (15) and (f_{q} subset F_{q}) be a measurable selection of (F_{q}).

So, let ( q, λ ) ∈ Q × [ 0, 1 ] be arbitrary and let f q, λ be a measurable selection of H m ( ⋅, q , q ˙ , which surely exists (see, e.g., [[27], Theorem 1.3.5]).

Since the multivalued operator U ( t ) ∩ F ( t, x ̄ ( t ) ) is measurable ([[57], Proposition III.4])), there exists a function v2 t) which is a measurable selection for V.

Since the multivalued operator U ( t ) ∩ F ( t, x ¯ ( t ) ) is measurable (Proposition III.4 [31]), there exists a function v 2 ( t ) which is a measurable selection for U.

Since the multi-valued operator (U t cap F t,bar{x}(t))) is measurable, there exists a function (v_{2}(t)) which is a measurable selection for U.

Since the multivalued operator (U t cap F t,bar{x}(t))) is measurable (Proposition III.4 [36]), there exists a function (v_{2}(t)) which is a measurable selection for U.

Since the nonempty closed set-valued operator (V t cap F t,bar{x}(t))) is measurable (Proposition III.4 [35]), there exists a function (v_{2}(t)) that is a measurable selection for (V t cap F t,bar{x}(t))).