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Let B be a finite, separable von Neumann algebra.
Let (K/F) be a finite separable field extension, (v) a discrete valuation of (F), and (w) an extension of (v) to (K).
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If $M/K^\wedge $ is a finite separable extension, then there exists a finite separable extension $L/K$ such that $M = K^\wedge \otimes _ K L$.
Let ( Ω, F, μ ) be a complete finite separable measure space, and let Y be a separable Banach space.
Theorem 3 Let ( Ω, F, μ ) be a complete finite separable measure space, and let Y be a separable Banach space.
If | I | = 1, we obtain the following corollary of Theorem 2. Corollary 1 Let ( Ω, F, μ ) be a complete finite separable measure space, and let Y be a separable Banach space.
"There's a finite amount of time.
Energy is a finite resource.
This Stradivarius — it's a finite supply.
But the opportunity is a finite one".
The NHS budget is a finite resource.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com