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Let be a cutoff function satisfying (2.6).
Let (phi(t)in C^{infty}(mathbb{R})) be a cutoff function satisfying (phi(t)=1) when (vert t vert leq3/2), (phi (t)=0) when (vert t vert geq2) and (vert phi(t) vert leq1) in (mathbb{R}).
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We may choose the test function in Definition 1.1, where is a cutoff function satisfying (3.2).
for any constant, where and is a cutoff function satisfying (2.2).
where is a cutoff function identically equal to 1 in and identically equal to 0 outside.
Here log+t is a cutoff function such that log+t = 1 for t ≤ e otherwise log+t = log t.
where ψ is a cutoff function defined by ψ ( t ) = 1 if | t | ≤ δ and ψ ( t ) = 0 if | t | ≥ 2 δ (δ is a positive constant small enough).
for each i = 1,..., m and in each Bσ/2 y i ), where is a cutoff function identically equal to 1 for t ≥ 1 and identically equal to 0 for t ≤ 1/2.
Yes, there should be a cutoff on some events.
Following [30], we put begin{aligned} tau = frac{1}{m}, e^{-frac{m^2}+zeta}+zeta }. end{aligned}Let (psi : mathbb{R } rightarrow [0,1]) be a smooth cutoff function such that (psi = 1) on ((-infty,1]) and (psi = 0) on ([2,infty )).
The idea is to approximate the vorticity by convolving it with a cutoff function.
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