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Let ((X,p)) be a compact partial metric space.
Let ((X,p)) be a compact partial metric space and let f be a mapping from ((X,p)) into itself satisfying pbigl(f(x),f y bigr)< p x,y) (6) for all (x,yin X) with (xneq y).
Let ((X,p)) be a compact partial metric space and let f be a mapping from ((X,p)) into itself which holds the contractive condition introduced in Theorem 11, i.e., pbigl(f(x),f y bigr)< p x,y) (21) for all (x,yin X) such that (xneq y).
Let ((X,p)) be a compact partial metric space and let f be a mapping from ((X,p)) into itself satisfying pbigl(f(x),f y bigr)< p x,y) (9) for all (x,yin X) with (xneq y) and pbigl(f(x),f(x bigr geq p x,x) (10) for all (xin X), then f has a unique fixed point.
Let ((X,p)) be a compact partial metric space and let f be a mapping from ((X,p)) into itself satisfying d_{p}bigl(f(x),f y bigr)leq d_{p} x,y) (11) for all (x,yin X) and pbigl(f(x),f y bigr)< p x,y) (12) for all (x,yin X) with (xneq y), then f has a unique fixed point.
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This is due to the fact that given a compact partial metric space ((X,p)), the associated metric space ((X,m_{p})) is not compact in general.
To define that class of manifolds, suppose that ( overline{M}) is a compact manifold with boundary ( partial M ne emptyset ) of dimension ( n +1 ).
First we give an example of a compact partial metric space whose induced metric space, obtained following (20), is not compact.
Let ((X,p)) be an O-compact partial metric space.
Therefore, the partial derivative equals T−I, where T is a compact operator.
Barry Press is a compact man.
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