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The effective channel bandwidth can be calculated from (30).

If interference exists between links that are within 2 hops, for the first link of the path, i.e., the link originates from the source, it has no previous link, so its equivalent bandwidth can be calculated from Equation 12.

First, the remaining bandwidth can be calculated by subtracting the current consumed bandwidth and the minimum guarantee bandwidth of non-greedy stations from their held bandwidth, i.e., initially half of the fair rate, on both uplink and downlink directions.

For the second link of the path, say link l, with previous link m, its equivalent bandwidth can be calculated as below: B l = B Inter, l CH ( l ) ≠ CH ( m ) B Inter, m × B Inter, l B Inter, m + B Inter, l CH ( l ) = CH ( m ) (17).

The percentage of bandwidth expansion can be calculated as, where  MHz is the bandwidth of the pulse.

Based on the response spectrum, the spectral moments and bandwidth parameter can be calculated.

Therefore, details may be considered as the original signal filtered within a specific bandwidth, which can be calculated from the equation, where F is 166*10−3 Hz as the sampling rate is one sample per three seconds and j is the stage number.

As intra-flow interference exists between links that are within 2 hops, transmission on link k may interfere with that on its previous link j and link j's previous link i, so we define equivalent bandwidth which can be calculated from Equations 12, 17, or 18.

It can be calculated by decreasing the bandwidth that can be allocated in prescheduled frames from the newly generated bandwidth, which is the difference between the bandwidths specified in the BRm- 1,x and BR m,n messages.

If we assume the bandwidth allocated in the zone is N*BW, the satisfaction rate S for the allocation can be calculated as follows.

Therefore, the overall input capacitance can be calculated using the time constant relationship for this measured 3-dB bandwidth (f c ): (16) C in = 1 2 π (10   M Ω ) f c.