Sentence examples for average first passage from inspiring English sources

The average first passage time has already been studied for this class of oscillator.

A specific algorithm is developed for the determination of the average first passage time as a function of initial and target conditions based on the experimental measurements.

For this purpose, we define the "Fold of Delay" as the average first passage time in the "clustered" case divided by the averaged first passage time obtained in the "uniform" case.

In order to check whether the simulations were reaction-limited or diffusion-limited, we compared the average mean first passage time (MFPT) of a ligand molecule in a receptor affinity zone to the reaction time-scale.

The mean first passage time at a given autoinducer concentration quantifies the average time that a cell takes to get activated or deactivated.

We consider the mean first passage time (MFPT).

If the user chooses to perform more simulations with the given number of walkers, mean first-passage times are averaged further and standard deviation of this mean over the number of simulations, with the given number of walkers, is calculated.

Then, the dynamical programming equations and their boundary and final time conditions for the control problems of maximizing reliability and of maximizing mean first-passage time are formulated from the averaged Itô equations by using the dynamical programming principle.

The average volume doubling times in the first passage in nude mice ranged from 8.2 in large cell carcinomas to 18.9 days in adenocarcinomas.

Finally, in the confidence-weighted multiple-choice condition, average scores on the test of the first passage (M = −6.05, SD = 20.23) did not significantly differ from those on the test of the second passage (M = 1.08, SD = 16.95; t 36) = −1.82, p = .08), suggesting, as in Experiment 1, that participants did not change their test-taking strategies from their first to their second tests.

Similarly, for participants in the confidence-weighted multiple-choice condition, the average score obtained on the test of the first passage (M = 4.82, SD = 17.11) did not differ significantly from that obtained on the test of the second passage [M = 4.16, SD = 18.29; t(49) = .22, p = .83].83]