Sentence examples for at the users side from inspiring English sources

We study the time-division duplex broadcast channel with initial assumption of channel state information (CSI) neither at the base station (BS) nor at the users' side.

A tensor-based CE scheme is presented in[9], in which the channel gains are estimated at the users' side using a non-iterative algebraic solution to nonlinear LS problems.

Consequently, the CE processing is done only at the users' side; therefore, in our system the relay can be simplified, and by decreasing transmission overhead we further increase the bandwidth efficiency.

The general analytical results for the average transmit power required to meet guaranteed performance at the users' side are difficult to obtain even without user selection due to joint optimization required over beamforming vectors and power allocation scalars.

Hence, implementing effective solutions allowing MSs to benefit from the advantages of multi-antenna systems without the extra burden of having multiple antennas physically present at the users' side has become a major issue for current communication systems.

Here, SNR t = P t / σ N 2 and SNR r = P r / σ N 2 represent the signal-to-noise power ratio at the users side and at the relay, respectively.

The frequency-domain representation of the received signal at user U k 's receiver can be written as R k ( n ) = 2 P r G R r ( n ) H k ( n ) + N k ( n ) (2). for n = 0 ∼ N c −1, where N k (n) denotes the AWGN at the user side with single-sided power spectral density N0.

Also, considering that the noise power is the same at the relay and the users side and E [ | N r ( n ) | 2 ] = E [ | N k ( n ) | 2 ] = 2 σ N 2, we find that (18) becomes MSE i → k ( n ) = N g N c 2 σ N 2 ( 2 P r G + 1 ).

As explained previously, we consider a uniform power delay profile for the individual channels between the users and the relay and thus E[|H0,i(n)|2] = E[|H1,i(n)|2] = 1 for all n and the noise power is the same at the relay and the users side and E | N r ( n ) | 2 = E | N i ( n ) | 2 = 2 σ N 2. (25) then becomes MSE k → i conv ( n ) = N g N c 2 σ N 2 ( 2 P t + 2 P r + 2 σ N 2 ).

This paper looks at the user side of sustainability.

The operations done at the user side are: a.