Sentence examples for arrive at the relation from inspiring English sources

Exact(1)

In order to do so, one has to turn this forward model backwards, to arrive at the relation SA ← SCR.

Similar(59)

Hence, there exists an element ψ ∈ W 0 1, p such that, up to a subsequence of θ → 0, we have ψ ε θ, θ ⇀ ψ in W 0 1, p as θ → 0. It remains to pass to the limit in (5.5), (5.7) as θ → + 0 and to show that in the limit we will arrive at the relations (7.3) and (7.1), respectively.

One finally arrives at the relation K m = K s + V r τ a = m t c a 0 + V r τ a (1).

Equating expressions for the optical force, and assuming that the laser beam has a radius R = 250 nm, we arrive at the following relation between κ and the laser power: κ = 1 corresponds to P = 0.74 mW, κ = 3 to P = 2.22 mW, κ = 5 to P = 3.71 mW, κ = 7 to P = 5.19 mW, and κ = 10 to P = 7.4 mW.

Describing ρ in terms of N, N min and m, we arrive at the following relation (2) ρ = 1 + m − N min N (1 + m ), which is plotted as the solid lines in Figure 3B and fits the data very well.

As can be seen from Equation (3), setting the nonlocal parameter e0a equal to zero, we arrive at the constitutive relations of the local theories.

Substituting (2.7) into (2.8) and collecting terms with the same powers of λ, we arrive at the following recursion relation: K G j − 1 = J G j, J G − 1 = 0, j ≥ 0, (2.9).

The approach is accurate, general and valid for all frequency ranges, since no simplifying are needed to arrive at the presented power flow relations.

end{aligned} (30) Since 2sin biggl( frac{t}{2} biggr) cos biggl( frac{t}{2} biggr) =sin ( t ), combining (29) and (30), after some calculations, we arrive at the following theorem including a relation between the central factorial numbers of the second kind and the array polynomials.

Substituting (18) into this relation, we arrive at the equation eta x, lambda) + frac{1}{2 pi i} int_{gamma} eta x, mu) tilde{r} x, lambda, mu),dmu= 0_{m},quad lambdain gamma, (25) with respect to (eta x, lambda) = ellvarphi x, lambda) - lambdavarphi x, lambda)).

Interestingly, in view of relation (1.4), we arrive at the following corollaries concerning Saigo fractional integral operator.

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