Sentence examples for array we get from inspiring English sources

To be specific, after the normalization of each array, we get a log-ratio denoted M and a mean intensity denoted A for each probe.

Knowing the intervals in suffix array we can get the positions.

These men are meant to be battle-toughened Nazi officers, but what we get is an array of discreetly amusing studies in mild neurosis.

By this way, we get the Gaussian array needed.

We get complete convergence for arrays of rowwise ρ ˜ -mixing random variables which are stochastically dominated by a random variable X.

When we plotted the relative expression (i.e. expressions of the individual probe sets divided by the mean of 11 arrays; Figure 2C), we got all the points, except for about ten outliers, back on the 45° line.

By applying Stirling interpolation expansion we get: begin{array}rcl@ textbf{y} = f(bar {textbf{x}}) + {tilde D_{Delta x}}f + frac{1}{{2!}}tilde D_{Delta x}^{2}f end{array} (15).

For thermal equilibrium condition N H =0, so we get begin{array}rcl@ Ra^{st}= frac{delta^{6}}{{alpha_{c}^{2}}} - Rn left(N_{A} - Leright) end{array} (51).

Then, we get begin{array}{*{20}l} boldsymbol{Psi}_{0} = left(mathbf{1} hat{breve{mathbf{h}}}_{0}^{T}right) times boldsymbol{Psi} text end{array} (29).

By using (left lceil frac {k}{r} right rceil - 1 geq frac {k}{r} - 1), we get begin{array}{*{20}l} frac{k}{n} leq frac{r}{r + ell}.

and integrating over ϕ we get begin{array}rcl@ 2 pi R intlimits_{theta=0}^{pi/2}lefrac{rho_{d_{d}}{pi} + rho_{s}frac{m+2}{2pi}cos^{m}thetaright) cos theta cosinthetasintheta {mathrm{d}}theta.