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"It gives me a lot of confidence that I can pull out a win like that when there are points of a match where you don't feel great..".
If are points of a CAT space and is the midpoint of the segment, which we will denote by, then the CAT inequality implies (1.2).
If x, y 1, y 2 are points of a CAT ( 0 ) space, and y 0 is the midpoint of the segment [ y 1, y 2 ], which will be denoted by y 1 ⊕ y 2 2, then the CAT ( 0 ) inequality implies that d 2 ( x, y 1 ⊕ y 2 2 ) ≤ 1 2 d 2 ( x, y 1 ) + 1 2 d 2 ( x, y 2 ) − 1 4 d 2 ( y 1, y 2 ).
Finally, we observe that if x, y 1, y 2 are points of a CAT ( 0 ) space and if y 0 is the midpoint of the segment [ y 1, y 2 ], which we will denote by y 1 ⊕ y 2 2, then the CAT ( 0 ) inequality implies d ( x, y 1 ⊕ y 2 2 ) 2 ≤ 1 2 d ( x, y 1 ) 2 + 1 2 d ( x, y 2 ) 2 − 1 4 d ( y 1, y 2 ) 2. (2.1).
If x, y 1, y 2 are points of a CAT ( 0 ) space and y 0 is the midpoint of the segment [ y 1, y 2 ] which we will denote by ( y 1 ⊕ y 2 ) / 2, then the CAT ( 0 ) inequality implies d 2 ( x, y 1 ⊕ y 2 2 ) ≤ 1 2 d 2 ( x, y 1 ) + 1 2 d 2 ( x, y 2 ) − 1 4 d 2 ( y 1, y 2 ).
Finally, we observe that if x, y 1, y 2 are points of a C A T ( 0 ) space and if y 0 is the midpoint of the segment [ y 1, y 2 ], then the C A T ( 0 ) inequality implies d ( x, y 0 ) 2 ≤ 1 2 d ( x, y 1 ) 2 + 1 2 d ( x, y 2 ) 2 − 1 4 d ( y 1, y 2 ) 2. (2.1).
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.
Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com