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Measurable operators are a solution of the problem (1.2) if and only if (22).
It is shown that the optimal maintenance decisions related to this problem are a solution of a continuous-time renewal-type dynamic programming equation.
Theorem 3.1 Suppose that, for some s ≥ 4, the functions u ( t, x ) are a solution of equation (3.1) corresponding to the initial data u 0 ∈ H s ( R ).
Here we show that the excitatory and inhibitory fluxes entering the population of type k, begin{aligned} phi_{Ek} x,t)&=int_{-infty}^{infty} Ebigl(x',tbigr) n_{Ek}bigl x-x'bigr),dx', phi_{Ik}(x,t)&=in_{Ek}bigl x-x'bigr I bigl(x',dx'gr) n_{Ik}bigl(x-x'bigr),dx',quad kin{E,I}, end{aligned} (A.1) are a solution of the phi_{Ik differential equations (10).
Then, the sequences {x n }, {y n }, {z n } generated by (3.2) converge strongly to the same point x* = P Ω Qx*, and (x*, y*) and ( x *, ȳ * ) are a solution of general system of variational inequalities (1.2) and a solution of general system of variational inequalities (1.6), respectively, where y* = P C (x* - λ2A2x*) and y ¯ * = P C ( x * - μ 2 B 2 x * ).
The boolean assignments σ i = v i * are a solution of the 3-SAT problem and, inversely if a solution of the 3-SAT problem exists then a minimal pathway satisfying the constraints exists and is the one obtained using only one of the hyperarcs for each X j among the ones whose head only contains ν j and vertices v i *.
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It was a solution of considerable difficulty.
Those people were a solution of a sort.
This u is a solution of (A).
That is, is a solution of (3.4).
Let be a solution of (1.1) satisfying.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com