Sentence examples for appropriately dimensioning from inspiring English sources

Exact(1)

Undoubtedly, the characterisation of network traffic flows is vitally important in understanding the dynamics of Internet traffic and in appropriately dimensioning network resources for network and systems management.

Similar(59)

where 1 is an appropriately dimensioned unit vector.

Using the Newton-Leibniz formula, for any appropriately dimensioned matrices N i, M i, the following equations are true: (14).

A useful property may now be derived by performing the following parameter transformation on the system in Eq. (27) such that (29) (30)where I are appropriately dimensioned identity matrices.

if there exit exist symmetric matrix X = X T > 0, and any appropriately dimensioned matrices V 1, V 2, such that the above LMI holds, ?

(8) where (x_{c} k)inmathbb{R}^{n}) is the state estimate of system (1), and (A_{ci}, B_{ci}, C_{ci}) are appropriately dimensioned parameters matrices to be determined.

provided that the scalar ?, symmetric matrices P ˆ 11, P ˆ 22 and appropriately dimensioned matrices P ˆ 12, X, Y, U, A ˆ, B ˆ, C ˆ, D ˆ satisfy the following LMIs, (15) (15).

end{aligned} (mathcal{P}) is the appropriately dimensioned square permutation matrix such that mathcal{P} [a_{1} quad a_{2} quad cdots quad a_{2m} ] = [ a_{1} quad a_{3} quad cdots quad a_{2m-1} qua_{2_{2} quad a_{4} quad cdots quad a_{2m} ].

Denote 〈 x, H y 〉 T = ∫ 0 T x T ( t ) H y ( t ) d t, in this article, we focus our attention on the quadratic supply rate E ( v, e, T ) = 〈 e, Q e 〉 T + 2 〈 e, S v 〉 T + 〈 v, R v 〉 T, where Q, S, R are appropriately dimensioned, and Q, R are symmetric matrices.

if there exist symmetric matrix P = P T > 0, any appropriately dimensioned matix V and a given scalar ?, such that the following inequality hold: [ - V A T - A V T - B P + V T - ? V A T V C T * - ? 2 I - ? B T D T * * ? V + ? V T 0 * * * - I ] < 0. (7).

end{aligned} (25) On the other hand, for any appropriately dimensioned invertible matrix M, the following zero equality holds: begin{aligned} 0=&2 bigl[e^{T} k)M+eta^{T} k)M bigr] Biggl[ A-KC_{1}-I)e(k)-KC_{2}e Biggl[ A-KC_{ bigr)+B_{1}-I e k -KC_{2}er) &+B_{2}gbigl(e bigl(k-tau(k) bigr)bigr)+B_{3}sum _{i=1}-I e k -KC_{2}e(i)g bigl(x(k-i) bigr)+(D_{1}-I e k -KC_{2}ek)-eta(k) bigl k-tau

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