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Since (mathbb {Y}) cannot be granulated anymore using the selector ((exists r.C_{i_t})), it follows that (x' in (exists r.C_{i_t})^mathcal {I}).
Since the partition (mathbb {Y}) cannot be granulated anymore using the concept (A), we have (Y_{i_j} subseteq A^mathcal {I}) or (Y_{i_j} cap A^mathcal {I}= emptyset ) for any (1 le j le k).
Take a job here and your friends may condemn you but you can be attracted by the challenge of trying to sell what can't be sold anymore using conventional methods.
Similarly as above, since the partition cannot be granulated anymore using any selector ((B=d)) with (d in range (B)), we have (Y_{i_j} subseteq (B=d)^mathcal {I}) or (Y_{i_j} cap (B=d)^mathcal {I}= emptyset ) for any (1 le j le k).
Since the partition (mathbb {Y}) cannot be granulated anymore using the selectors (ge,l,r) (when (l > 0)) and (le,l,r) (when (l < #Delta ^mathcal {I})), we have that (x' in (ge,l,r)^mathcal {I}) and (x' in (le,l,r)^mathcal {I}).
A Princeton Ph.D. candidate by the name of Benjamin Lauderdale has actually proven that John McCain isn't a maverick anymore, using the maths!
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If you have an old board that you don't use anymore use that one so you don't ruin your good board.
that isn't useful anymore; avoid using a sock that's still in regular use.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com