Sentence examples for and by commutativity of from inspiring English sources

The phrase "and by commutativity of" is correct and usable in written English.
It can be used in mathematical or logical contexts to refer to the property of commutativity, which states that the order of operations does not affect the outcome.
Example: "We can simplify the expression further, and by commutativity of addition, we can rearrange the terms."
Alternatives: "due to the commutative property of" or "because of the commutativity of".

Exact(1)

Since and, by commutativity of and, we have (261).

Similar(59)

On the other hand, since gx = F x, y) and gy = F y, x), by commutativity of F and g, we have g ( g x ) = g ( F ( x, y ) ) = F ( g x, g y ), g ( g y ) = g ( F ( y, x ) ) = F ( g y, g x ).

Since g x = F ( x, y ) and g y = F ( y, x ), by commutativity of F and g, we have g ( g x ) = g ( F ( x, y ) ) = F ( g x, g y ) and g ( g y ) = g ( F ( y, x ) ) = F ( g y, g x ).

Since g x = F ( x, y, z, w ), g y = F ( y, z, w, x ), g z = F ( z, w, x, y ), and g z = F ( z, w, x, y ), by commutativity of F and g, we have.

By commutativity of A and by equation (1), we have y ∈ W ( x ) ⊆ y ∈ W ( T ( x ) ) = T ( W ( x ) ) ⊆ T ( y ), which is a contradiction.

Since G X = F X, by commutativity of f and g, we have G G X = G F X = F G X .Let G X = A. Then G A = F A. Thus, A is another coincidence point of f and g.

By commutativity of Diagram (11), we have (pi ^mathrm{un}((h x,n_i)) _x)=n_i).

Again, by commutativity of (11), we have ((w x,n_i))_v in ker (pi ^mathrm{un})) for all (v in X^*).

On the other hand, (pi (k) = 1) implies ( pi (k_v) = 1) for all (v in X^n); moreover, the (S_d^{(n)} -coordinate of (varphi _n(k)) is (1), by commutativity of Diagram (14).

By commutativity of diagram (8), the map (rsGamma:Xrightrightarrows X) also has a fixed point (x_{omega}=rs y_{omega})), (y_{omega}in Gamma (x_{omega})) satisfying ({x_{omega},y_{omega}}) are ω-near, i.e., (x_{omega}) is an ω-fixed point for Γ.

Since g x=F x,y) and g y=F y,x), by the commutativity of F and g, we have g ( g ( x ) ) = g ( F ( x, y ) ) = F ( gx, gy ), and g ( gy ) = g ( F ( y, x ) ) = F ( gy, gx ).

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