The phrase "again integrated" is correct and usable in written English.
It can be used when referring to something that has been integrated once more into a system or process after a previous integration.
Example: "The software has been again integrated into the main framework to enhance its functionality."
Alternatives: "reintegrated" or "integrated once more".
Later, the Ethnology Team was again integrated into the Institute of History and Language.
When the input exceeded the maximum static friction, an overshoot response was initiated, and the input was again integrated to reach the maximum static friction.
Those preferring a higher resolution can pay $670 for the original, 49-inch Mi TV 2. Xiaomi has again integrated an Android (well, MIUI -based entertainMIUI -based.
After the Austro-Hungarian Compromise of 1867, Klausenburg and all of Transylvania were again integrated into the Kingdom of Hungary.
Again, integrated H NMR data provides the primary characterization of this assignment, and integrations are largely in agreement with the assigned structure.
Then again, integrating a mobile operating system built to hook into apps, and a desktop one built around a browser, is quite a challenge.
A settlement that leaves the militias in place, or that again integrates them haphazardly into the national army, will only perpetuate the current mayhem.
Naqoyqatsi The third part of Mr. Reggio's series, following "Koyaanisqatsi" and "Powaqqatsi," again integrates images, but here the picture turns grimmer in its depiction of technological regimentation and the seeming inevitablity of war.
Once again integrate from to to obtain (2.49).
From Eq. (8), the bound on G and again integrating κ, we immediately see that each path of Q is bounded by the stochastic process Y defined by Y t)=u(t)+varGamma^{-2} bigl(mathbb{I}_{3}-vartheta(t) bigr) C_{G}+ int _{0}^{t} kappa t-s varSigma,dW(s).
Again integrating the above inequality from t to k ( t ) we find x ( k ( t ) ) ≥ h 1 α ( x [ k ( t ) ] ) ∫ t k ( t ) ( a ( s 2 ) ∫ t s 2 ∫ t s 1 p ( s ) Δ s Δ s 1 ) 1 α Δ s 2. Finally, dividing the above inequality by h 1 α ( x ( k ( t ) ) ) and taking the lim sup of both sides of the above inequality as t → ∞, we obtain a contradiction to (3.5).
