Sentence examples for admissible measures from inspiring English sources

Exact(2)

Given the character:lambda] weightings can vary, there is considerable flexibility in the family of admissible measures.

Admissible measures of diversity allow specification of the number of types (species, alleles, etc).

Similar(57)

Consider a p-admissible vector measure (mu ).

Let (1le padmissible vector measure.

(Heuristic definition) Let us consider (1le p< infty ) and a p-admissible vector measure (mu =(mu _0,ldots,mu _k)) in (mathbb {R}).

end{aligned}Let us consider the projection (P ,W^{k,p}(Delta,mu )longrightarrow prod _{j=0}^k L^{p}(Delta,mu _j)), given by (Pf= f,f',ldots,f^{ k)})). Let (1le padmissible vector measure.

For each (1le padmissible vector measure (mu ) in (mathbb {R}), consider the Banach space (prod _{j=0}^k L^{p}(Delta,mu _j)) with the norm begin{aligned} Vert fVert _{prod _{j=0}^k L^{p}(Delta,mu _j)} = left( sum _{j=0}^k left| f_jright| _{L^{p}(mu _j)}^p right) ^{1/p} end{aligned}for every (f=(f_0,ldotsdots,f_k)in prod _{j=0}^k L^{p}(Delta,mu _j)).

As in forensic assessment, the Type II Error (classification of malingered injury as real) is not admissible; the psychometric measure is not sufficient evidence of psychological injury.

Assume that u is such that U is admissible and the measure w ( t ) d t is non-degenerate with respect to U q p. (i) Let 1 ≤ q < ∞.

Assume that u is such that U is admissible and the measure w ( t ) d t is non-degenerate with respect to U q. (i) Let 0 < p ≤ 1, p ≤ q < ∞.

Assume that u is such that U is admissible and the measure w ( t ) d t is non-degenerate with respect to U q p. Let { x k } be any discretizing sequence for φ defined by (3.3).

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